The maximum current that each output can handle is 500mA. However, it's recommended to derate the current to 350mA for reliable operation.
You can add a flyback diode (e.g., 1N4007) in parallel with the inductive load to protect the ULN2068B from back-EMF. The diode should be connected in the reverse direction of the load current.
The minimum input voltage required is 4.5V, but it's recommended to use a minimum of 5V for reliable operation.
Yes, the ULN2068B can be used to drive a relay. However, ensure that the relay's coil current is within the ULN2068B's output current rating (500mA). Also, add a flyback diode to protect the ULN2068B from back-EMF.
The power dissipation of the ULN2068B can be calculated using the formula: Pd = (Vin - Vout) x Iout, where Vin is the input voltage, Vout is the output voltage, and Iout is the output current.