TPS3125J18DBVT datasheet by Texas Instruments

TPS3125J18DBVT Frequently Asked Questions (FAQs)

• What is the maximum input voltage that can be applied to the TPS3125J18DBVT?
  The maximum input voltage that can be applied to the TPS3125J18DBVT is 18V, as specified in the datasheet. However, it's recommended to derate the input voltage to 15V to ensure reliable operation and to prevent damage to the device.
• How do I ensure the TPS3125J18DBVT is stable and doesn't oscillate?
  To ensure stability, it's essential to follow the layout guidelines provided in the datasheet, including keeping the input and output capacitors close to the device, using a low-ESR output capacitor, and minimizing the loop area of the power traces. Additionally, the datasheet recommends a specific compensation network to ensure stability.
• What is the minimum output capacitance required for the TPS3125J18DBVT?
  The minimum output capacitance required for the TPS3125J18DBVT is 10uF, as specified in the datasheet. However, it's recommended to use a higher value capacitor, such as 22uF or 47uF, to ensure stability and to filter out high-frequency noise.
• Can I use the TPS3125J18DBVT in a high-temperature environment?
  The TPS3125J18DBVT is rated for operation up to 125°C, but it's essential to derate the output current and input voltage as the temperature increases to prevent damage to the device. The datasheet provides a thermal derating curve to help designers determine the maximum output current and input voltage at elevated temperatures.
• How do I calculate the power dissipation of the TPS3125J18DBVT?
  The power dissipation of the TPS3125J18DBVT can be calculated using the equation: Pd = (Vin - Vout) x Iout + (Vin x Iq), where Vin is the input voltage, Vout is the output voltage, Iout is the output current, and Iq is the quiescent current. The datasheet provides the quiescent current and other relevant parameters to help designers calculate the power dissipation.